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Proof step 8 from proof refine-is-log-empty (previous step)

fi = fi1, fi0 = fi2, ginval = ginval2, gstore = gstore2, maxino = maxino0, nx = nx0, remove-refsize0(istore1) = istore1, remove-refsize0(gstore2) = gstore2, elems nx0 ∩ ginval0 = ∅, dom gstore2 ∪ elems nx0 = dom gstore0 ∪ ginval0, btree-inv(rp, adr, istore2, istore1, zh, fi2, fi1), inv(istore1), inv(istore2), inv(gstore2), inv(gstore0 \ ginval0), ri-inj(fi1), ri-inj(fi2), istore1 ⊑ istore2, pstate = unbuffered → syn0, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx0 ≠ [] ∧ pstate.lnum = nx0.last ∧ pstate.lnum ∈ gstore0 ⊦ ⟨syn := nx = []⟩ (nx0 = [] ↔ syn), dups(nx0)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

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