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Proof step 48 from proof refine-sync (previous step)

err = err1, remove-refsize0(istore1) = istore1, remove-refsize0(gstore2) = gstore2, elems nx0 ∩ ginval0 = ∅, dom gstore2 ∪ elems nx0 = dom gstore0 ∪ ginval0, btree-inv(rp, adr, istore2, istore1, zh, fi2, fi1), inv(istore1), inv(istore2), inv(gstore2), inv(gstore0 \ ginval0), ri-inj(fi1), ri-inj(fi2), istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx0 ≠ [] ∧ pstate.lnum = nx0.last ∧ pstate.lnum ∈ gstore0, ⌊err1⌋ ∨ err1 = ESUCCESS ⊦ ⟨if err = ESUCCESS then syn := true else syn := ?⟩ ((syn ↔ err = ESUCCESS) ∧ err1 = err), pstate = readonly, pstate = unbuffered, dups(nx0)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

Additional information