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Proof step 11 from proof transitivity (previous step)

key0 = datakey(ino0, ino1), key0 < key1, key1.ino ≤ ino, ino < key0.ino ∨ ¬ key0.inode? ∧ ino = key0.ino ⊦ ¬ key1.inode? ∧ ino = key1.ino

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
datakey(ino0, ino1) < key1, key1.ino ≤ ino, ino < ino0 ∨ ino = ino0 ⊦ ¬ key1.inode? ∧ ino = key1.ino

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ datakey(m, m0).inode?; (s)% ⊦ datakey(m, m0).ino = m; (s)