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Proof step 13 from proof in-keyrange-in-ri-data (previous step)

n < nused, n < # zbrar, adr ∈ (n + 1 = nused ⊃ ri |> zbrar[n - 1].key;(ri |> zbrar[n - 1].key) |≤ zbrar[n].key), nused ≤ # zbrar ⊦ n = 0, adr ∈ ri

User applied rule case distinction

And obtained the following new goals

Proof step 14:
n + 1 = nused, n < # zbrar, n < nused, adr ∈ ri |> zbrar[n - 1].key, nused ≤ # zbrar ⊦ n = 0, adr ∈ ri
Proof step 19:
n < # zbrar, n < nused, adr ∈ (ri |> zbrar[n - 1].key) |≤ zbrar[n].key, nused ≤ # zbrar ⊦ n + 1 = nused, n = 0, adr ∈ ri

Rule argument

pos: left 3

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