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Proof step 16 from proof in-keys (previous step)

n1 < nused0, m + nused0 < # zbrar, m < # zbrar ⊦ zbrar[m + n1 + 1].key = zbrar[m].key, zbrar[m + n1 + 1].key ∈ keys(zbrar, m + 1, nused0), ∃ n. n < nused0 ∧ zbrar[(m + 1) + n].key = zbrar[m + n1 + 1].key

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: n1

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: n1