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Proof step 4 from proof in-playload-data (previous step)

sorted(zbrar, 0, n + 0), n + 0 ≤ # zbrar ⊦ adr ∈ payload(zbrar, n, 0) ↔ (∃ m0. n ≤ m0 ∧ m0 < n + 0 ∧ zbrar[m0].entry? ∧ zbrar[m0].adr = adr)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
sorted(zbrar, 0, n), adr ∈ ∅, n ≤ # zbrar ⊦

Rule argument

Additional information

Used simplifier rules: payload-base: ⊦ payload(zbrar, m, 0) = ∅;% ⊦ m ≤ n → (n < m ↔ false); (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n + 0 = n; (s)