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Proof step 1 from proof look-empty (conclusion)

⊦ look(bv, key, adr, ∅) ↔ ¬ bv

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: look: ⊦ look(bv, key, adr, ri) ↔ (bv ↔ key ∈ ri) ∧ (bv → adr = ri[key]);% ⊦ ¬ key ∈ ∅; (s)