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Proof step 9 from proof look-subrange (previous step)

n < nused, n < # zbrar, key ∈ (n = 0 ⊃ (nused = 1 ⊃ ri;ri |≤ zbrar[0].key);(n + 1 = nused ⊃ ri |> zbrar[n - 1].key;(ri |> zbrar[n - 1].key) |≤ zbrar[n].key)), nused ≤ # zbrar ⊦ nused = 1, key ∈ ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
n < # zbrar, n < nused, key ∈ (n = 0 ⊃ ri |≤ zbrar[0].key;(n + 1 = nused ⊃ ri |> zbrar[n - 1].key;(ri |> zbrar[n - 1].key) |≤ zbrar[n].key)), nused ≤ # zbrar ⊦ nused = 1, key ∈ ri

Proof step 9 from proof look-subrange (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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