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Proof step 2 from proof payload-one (previous step)

m < # zbrar ⊦ payload(zbrar, m, 1) = (zbrar[m].entry? ⊃ (∅)[zbrar[m].key, zbrar[m].adr];∅)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m < # zbrar ⊦ payload(zbrar, m, 1) = (zbrar[m].entry? ⊃ (∅)[zbrar[m].key, zbrar[m].adr];∅)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic