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Proof step 5 from proof range (previous step)

nused ≤ # zbrar ⊦ # zbrar = 0, key-range(zbrar, 0, nused, ri) = (nused = 1 ⊃ ri;ri |≤ zbrar[0].key), nused = 0

User applied rule case distinction

And obtained the following new goals

Proof step 6:
nused ≤ # zbrar ⊦ # zbrar = 0, key-range(zbrar, 0, nused, ri) = ri |≤ zbrar[0].key, nused = 0, nused = 1

Rule argument

pos: right 2

Additional information

Used simplifier rules: range-one: ⊦ key-range(zbrar, 0, 1, ri) = ri;