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Proof step 13 from proof unmodified-clean-eq-keys (previous step)

# zbrar0 = BRANCH_SIZE, BRANCH_SIZE = # zbrar1, iast[adr] = indexnode(save(zbrar0, 0, nused), bv, nused), n < nused, n < BRANCH_SIZE, adr ∈ iast, nused ≤ BRANCH_SIZE, n < BRANCH_SIZE → save(zbrar1, 0, nused)[n] = save(zbrar0, 0, nused)[n] ⊦ zbrar1[n].key = zbrar0[n].key

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
# zbrar0 = BRANCH_SIZE, BRANCH_SIZE = # zbrar1, iast[adr] = indexnode(save(zbrar0, 0, nused), bv, nused), save(zbrar1[n]) = save(zbrar0[n]), n < BRANCH_SIZE, n < nused, adr ∈ iast, nused ≤ BRANCH_SIZE ⊦ zbrar1[n].key = zbrar0[n].key

Rule argument

Additional information

Used simplifier rules: n < nused, nused ≤ BRANCH_SIZE ⊦ save(zbrar, 0, nused)[n] = save(zbrar[n]); (s)