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Proof step 3 from proof unmodified-clean-leaf-subseteq (previous step)

iast1[adr] = save(mkznode(rp1, zbrar1, bv1, false, nused1)), iast0[adr] = save(mkznode(rp0, zbrar0, bv0, false, nused0)), adr ∈ iast1, adr ∈ iast0, iast0 ⊆ iast1 ⊦ (bv0 ↔ bv1) ∧ nused0 = nused1

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: store, inst: index-store-address-store name: Subset seq: ⊦ iast ⊆ iast0 ↔ (∀ adr. adr ∈ iast → adr ∈ iast0 ∧ iast[adr] = iast0[adr]) subst: [iast0, iast] → [iast1, iast0] flags: <all paths>

Additional information

Used terms: iast1, iast0