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Proof step 6 from proof unmodified-clean-leaf-subseteq (previous step)

iast1[adr] = save(mkznode(rp1, zbrar1, bv1, false, nused1)), iast0[adr] = save(mkznode(rp0, zbrar0, bv0, false, nused0)), adr ∈ iast1, adr ∈ iast0, adr ∈ iast0 → adr ∈ iast1 ∧ iast0[adr] = iast1[adr] ⊦ (bv0 ↔ bv1) ∧ nused0 = nused1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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