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Proof step 1 from proof unmodified-dirty (conclusion)

⊦ unmodified(adr, mkznode(rp, zbrar, bv, true, nused), iast)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: unmodified: ⊦ unmodified(adr, znd, iast) ↔ ¬ znd.dirty → adr ∈ iast ∧ iast[adr] = save(znd);% ⊦ mkznode(r, zbrar, boolvar, boolvar0, m).dirty ↔ boolvar0; (s)