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Proof step 17 from proof sorted-lt-h (previous step)

zbrar[n].key < zbrar[n + 1].key, n < # zbrar, sorted(zbrar, n + 1, m + 1), m4 ≤ m, m1 ≤ m, ∀ m2, m3, zbrar0, n0. ¬ m < m2 ∧ ¬ m < m3 ∧ sorted(zbrar0, n0, m + 1) → (zbrar0[n0 + m2].key < zbrar0[n0 + m3].key ↔ m2 < m3) ⊦ zbrar[n + m1 + 1].key < zbrar[n + m4 + 1].key ↔ m1 < m4

User applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: m1, m4, zbrar, n + 1 abort: F discard: F computed: T

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: m1, m4, zbrar, n + 1