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Proof step 3 from proof sorted-rec1 (previous step)

sorted(zbrar, n, m + 1) ⊦ sorted(zbrar, n + 1, m)

User applied rule structural induction

And closed the goal!

Rule argument

indvar: m

Additional information

Used simplifier rules: sorted-one: ⊦ sorted(zbrar, n, 1);%sorted-base: ⊦ sorted(zbrar, n, 0);%sorted-rec: ⊦ sorted(zbrar, n, m + 2) ↔ n < # zbrar ∧ zbrar[n].key < zbrar[n + 1].key ∧ sorted(zbrar, n + 1, m + 1);%nat freely generated by 0, +1;;% ⊦ m +1 = m + 1; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic