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Proof step 4 from proof load-branches-last (previous step)

⊦ load(brar, m + 1, nused)[m, load(brar[m])] = load(brar, m, nused)[m + nused, load(brar[m + nused])]

User applied rule structural induction

And obtained the following new goals

Proof step 5:
∀ brar, m. load(brar, m + 1, nused0)[m, load(brar[m])] = load(brar, m, nused0)[m + nused0, load(brar[m + nused0])] ⊦ load(brar, m + 1, nused0 +1)[m, load(brar[m])] = load(brar, m, nused0 +1)[m + nused0 +1, load(brar[m + nused0 +1])]

Rule argument

indvar: nused

Additional information

Used simplifier rules: load-branches-base: ⊦ load(brar, m, 0) = mkzbrarray(BRANCH_SIZE);%nat freely generated by 0, +1;;% ⊦ n + 0 = n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic