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Proof step 16 from proof align-down-add-ls (previous step)

(n0 + n1) % m = 0, n0 % m + n1 < m, n0 ≤ n0 + n1 ⊦ n0 % m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
(n0 + n1) % m = 0, n0 % m + n1 < m ⊦ n0 % m = 0

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m ≤ m + n; (s)