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Proof step 5 from proof aligndown-is-zero (previous step)

m / n * n = 0, n ≤ m ⊦ m % n = 0, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
m / n = 0, n ≤ m ⊦ m % n = 0, n = 0

Rule argument

Additional information

Used simplifier rules: mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ m ≠ 0 → (m * n = 0 ↔ n = 0); (s)