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Proof step 6 from proof aligndown-sub-add-sub (previous step)

⊦ n2 - (n2 % n = 0 ⊃ n2;n2 / n * n) = n2 % n, n = 0

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 7:
⊦ n2 % n = 0, n2 - n2 / n * n = n2 % n, n = 0

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ m - m = 0; (s)