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Proof step 4 from proof alignup-is-bigger (previous step)

(n0 % m = 0 ⊃ n0;m * n0 / m + m) < n0 ⊦ m = 0

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Proof step 5:
m * n0 / m + m < n0 ⊦ n0 % m = 0, m = 0

Rule argument

pos: left 1

Additional information

Used simplifier rules: ⊦ ¬ n < n; (s)