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Proof step 11 from proof eq1 (previous step)

(m + n0) / m * m ≤ n0 + 1, ∀ m. (n0 + m) / m * m ≤ n0 → m = 0 ⊦ n0 % m + 1 = m, m = 0

User applied rule all left

And obtained the following new goals

Proof step 12:
(m + n0) / m * m ≤ n0 + 1, (n0 + m) / m * m ≤ n0 → m = 0 ⊦ n0 % m + 1 = m, m = 0

Rule argument

pos: left 2 terms: m abort: F discard: T computed: T

Additional information

Used terms: m