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Proof step 4 from proof eq1 (previous step)

(n0 +1 + m) / m * m ≤ n0 +1, ∀ m. (n0 + m) / m * m ≤ n0 → m = 0 ⊦ m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
((n0 + 1) + m) / m * m ≤ n0 + 1, ∀ m. (n0 + m) / m * m ≤ n0 → m = 0 ⊦ m = 0

Rule argument

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m +1 = m + 1; (s)