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Proof step 2 from proof is-aligned-add-diff-ls (previous step)

m < n ⊦ n = 0, is-aligned(m + (n - m), n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ is-aligned(n, m) ↔ n % m = 0

Rule argument

Additional information

Used simplifier rules: is-aligned-def: ⊦ is-aligned(n, m) ↔ n % m = 0;%n ≠ 0 ⊦ n % n = 0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ n < m → (m - n) + n = m; (s)% ⊦ m < n → n ≠ 0; (s)