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Proof step 2 from proof is-aligned-aligndown-zero-ls (previous step)

is-aligned(m, n) ⊦ n ≤ m ↔ m ≠ 0, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m ≠ 0 ⊦ is-aligned(n, m) → (m ≤ n ↔ n ≠ 0)

Rule argument

Additional information

Used simplifier rules: is-aligned-le-eq-zero: m ≠ 0 ⊦ is-aligned(n, m) → (m ≤ n ↔ n ≠ 0);% ⊦ m ≤ 0 ↔ m = 0; (s)