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Proof step 2 from proof is-aligned-is-aligned-mod (previous step)

is-aligned(m, n), is-aligned(n0, n) ⊦ n = 0, n0 = 0, is-aligned(m % n0, n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ is-aligned(n, m) ↔ n % m = 0
Proof step 4:
n0 % n = 0, m % n = 0 ⊦ (m % n0) % n = 0, n = 0, n0 = 0

Rule argument

Additional information

Used simplifier rules: is-aligned-def: ⊦ is-aligned(n, m) ↔ n % m = 0;