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Proof step 2 from proof is-aligned-ls-eq-zero (previous step)

is-aligned(n, m) ⊦ n < m ↔ n = 0, m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ is-aligned(n, m) ↔ n % m = 0

Rule argument

Additional information

Used simplifier rules: is-aligned-def: ⊦ is-aligned(n, m) ↔ n % m = 0;% ⊦ m < n → m % n = m; (s)% ⊦ m < n → n ≠ 0; (s)% ⊦ 0 < m ↔ m ≠ 0; (s)