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Proof step 1 from proof is-aligned-mod-alignment (conclusion)

n0 ≠ 0, m ≠ 0 ⊦ is-aligned(n % (n0 * m), m) ↔ is-aligned(n, m)

System applied rule normalize

And obtained the following new goals

Proof step 2:
⊦ is-aligned(n % (n0 * m), m) ↔ is-aligned(n, m), m = 0, n0 = 0

Rule argument

Additional information