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Proof step 2 from proof is-aligned-not-multiples (previous step)

⊦ is-aligned(m, n * m) ↔ n = 1, m = 0, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ is-aligned(n, m) ↔ n % m = 0
Proof step 4:
m % (n * m) = 0 ⊦ m = 0, n = 0, n = 1

Rule argument

Additional information

Used simplifier rules: is-aligned-def: ⊦ is-aligned(n, m) ↔ n % m = 0;%n ≠ 0 ⊦ n % n = 0; (s)%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ m0 * 1 = m0; (s)