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Proof step 2 from proof is-aligned-of-mod (previous step)

is-aligned(m0, m1) ⊦ is-aligned(n % m0, m1) ↔ is-aligned(n, m1), m0 = 0, m1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ is-aligned(n, m) ↔ n % m = 0
Proof step 4:
m0 % m1 = 0 ⊦ (n % m0) % m1 = 0 ↔ n % m1 = 0, m0 = 0, m1 = 0

Rule argument

Additional information

Used simplifier rules: is-aligned-def: ⊦ is-aligned(n, m) ↔ n % m = 0;