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Proof step 2 from proof is-aligned-still-space (previous step)

n0 < n % n0 + n1, is-aligned(n0, n1), is-aligned(n, n1) ⊦ n0 = 0, n1 = 0, is-aligned(n, n0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ is-aligned(n, m) ↔ n % m = 0
Proof step 4:
n0 % n1 = 0, n % n1 = 0, n0 < n % n0 + n1 ⊦ n % n0 = 0, n0 = 0, n1 = 0

Rule argument

Additional information

Used simplifier rules: is-aligned-def: ⊦ is-aligned(n, m) ↔ n % m = 0;% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic