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Proof step 4 from proof rounded-help2 (previous step)

2 * m2 = m2 + m2, m1 < m2, n0 < m2, 2 * m2 ≤ n0 + m1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n0 < m2, m1 < m2, 2 * m2 ≤ n0 + m1 ⊦

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + m = 2 * m; (s)