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Proof step 14 from proof indices-where-in-h (
previous step
)
n < m0, n < # ar, m0 < # ar, n + 1 < # ar, φ(ar[n]), φ(ar[m0]), ∀ ar, n, φ. m0 ≤ # ar → (n ∈ ar.indicesWhere(φ, m0) ↔ n < m0 ∧ φ(ar[n])) ⊦ n = m0, n ∈ ar.indicesWhere(φ, m0)
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 7 terms: ar, n, φ
Additional information
Used simplifier rules: ⊦ m < n → m ≤ n; (s) Used terms: ar, n, φ