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Proof step 1 from proof indices-where-in (conclusion)

⊦ n ∈ ar.indicesWhere(φ) ↔ n < # ar ∧ φ(ar[n])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ar.indicesWhere(φ) = ar.indicesWhere(φ, # ar)
Proof step 3:
⊦ n ∈ ar.indicesWhere(φ, # ar) ↔ n < # ar ∧ φ(ar[n])

Rule argument

spec: <toplevel> name: indiceswhere seq: ⊦ ar.indicesWhere(φ) = ar.indicesWhere(φ, # ar) subst: [φ, ar] → [φ, ar] flags: <all paths>

Additional information

Used terms: φ, ar