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Proof step 2 from proof map-ifn-at (previous step)

n < # ar, m ≤ # ar ⊦ ar.mapIf(φ, f, m)[n] = (n < m ∧ φ(ar[n]) ⊃ f(ar[n]);ar[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n < # ar, m ≤ # ar ⊦ ar.mapIf(φ, f, m)[n] = (n < m ∧ φ(ar[n]) ⊃ f(ar[n]);ar[n])

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic