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Proof step 19 from proof map-indices-at (previous step)

m < # ar, nx0 < # ar, n < # ar, n ∈ nx0, ∀ ar0, n0, f0. nx0 < # ar0 ∧ n0 < # ar0 → ar0.mapIndices(nx0, f0)[n0] = (n0 ∈ nx0 ⊃ f0(ar0[n0]);ar0[n0]) ⊦ ar[m, f(ar[m])].mapIndices(nx0, f)[n] = f(ar[n]), m = n, dups(nx0), m ∈ nx0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
n < # ar, nx0 < # ar, m < # ar, n ∈ nx0, ∀ ar0, n0, f0. nx0 < # ar0 ∧ n0 < # ar0 → ar0.mapIndices(nx0, f0)[n0] = (n0 ∈ nx0 ⊃ f0(ar0[n0]);ar0[n0]) ⊦ ar[m, f(ar[m])].mapIndices(nx0, f)[n] = f(ar[n]), dups(nx0), m ∈ nx0

Proof step 19 from proof map-indices-at (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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