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Proof step 17 from proof valid-indices-nodups-h (previous step)

n0 < # ar, dups(ar.indicesWhere(φ, n0)), ∀ ar0, φ0. ¬ dups(ar0.indicesWhere(φ0, n0)) ∨ ¬ n0 ≤ # ar0 ⊦ φ(ar[n0])

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: ar, φ

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n; (s) Used terms: ar, φ