n < # ar0 + # ar1 ⊦ (ar0 + ar1)[n] = (n < # ar0 ⊃ ar0[n];ar1[n - # ar0])
Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic