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Proof step 2 from proof append-at1-simp2 (previous step)

n0 + n2 = # ar0, n1 < n2 ⊦ (ar0 + ar1)[n0 + n1] = ar0[n0 + n1]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n0 + n2 = # ar0, n1 < n2 ⊦ (ar0 + ar1)[n0 + n1] = ar0[n0 + n1]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic