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Proof step 3 from proof append-at1 (previous step)

n < # ar0 ⊦ (ar0 + ar1)[n] = ar0[n]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ ar0 + ar1 = copy(ar1, 0, resize(ar0, # ar0 + # ar1), # ar0, # ar1)
Proof step 5:
n < # ar0 ⊦ copy(ar1, 0, resize(ar0, # ar0 + # ar1), # ar0, # ar1)[n] = ar0[n]

Rule argument

spec: <toplevel> name: append seq: ⊦ ar0 + ar1 = copy (ar1, 0, resize(ar0, # ar0 + # ar1), # ar0, # ar1) subst: [ar1, ar0] → [ar1, ar0] flags: <all paths>

Additional information

Used terms: ar1, ar0