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Proof step 20 from proof append-inj (previous step)

# ar0 = # ar1, # ar = # ar2, ∀ n. n < # ar1 + # ar2 → (ar0 + ar)[n] = (ar1 + ar2)[n] ⊦ # ar = # ar2 ∧ (∀ n. n < # ar → ar[n] = ar2[n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic