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Proof step 2 from proof append-right-size0 (previous step)

# ar1 = 0 ⊦ ar0 + ar1 = ar0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ ar0 + ar1 = ar0 ↔ # ar1 = 0
Proof step 4:
⊦ (ar + ar0) + ar1 = ar + ar0 + ar1

Rule argument

Additional information

Used simplifier rules: append-prefix-left: ⊦ ar0 + ar1 = ar0 ↔ # ar1 = 0;%append-a: ⊦ (ar + ar0) + ar1 = ar + ar0 + ar1;