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Proof step 4 from proof array-split-elim-size (previous step)

# ar = n0 + n1 ⊦ ∃ ar0, ar1. ar = ar0 + ar1 ∧ # ar0 = n0 ∧ # ar1 = n1

User applied rule exists right

And obtained the following new goals

Proof step 5:
# ar = n0 + n1 ⊦ ar = subarray(ar, 0, n0) + subarray(ar, n0, n1) ∧ # subarray(ar, 0, n0) = n0 ∧ # subarray(ar, n0, n1) = n1

Rule argument

pos: right 1 terms: subarray(ar, 0, n0), subarray(ar, n0, n1) abort: F discard: T computed: F

Additional information

Used terms: subarray(ar, 0, n0), subarray(ar, n0, n1)