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Proof step 4 from proof array-split1 (previous step)

n ≤ # ar ⊦ ar = subarray(ar, 0, n) + subarray(ar, n, # ar - n) ∧ # subarray(ar, 0, n) = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
n ≤ # ar ⊦ ar = subarray(ar, 0, n) + subarray(ar, n, # ar - n)

Rule argument

Additional information

Used simplifier rules: ⊦ # subarray(ar, m, n) = n; (s)