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Proof step 2 from proof copy-append (previous step)

n + m1 ≤ # ar0 + # ar1, # ar0 ≤ n ⊦ copy(ar0 + ar1, n, ar2, m0, m1) = copy(ar1, n - # ar0, ar2, m0, m1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
n = n0 + # ar0, # ar0 ≤ n, n + m1 ≤ # ar0 + # ar1 ⊦ copy(ar0 + ar1, n, ar2, m0, m1) = copy(ar1, n0, ar2, m0, m1)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, # ar0, n0]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, # ar0, n0