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Proof step 1 from proof copy-shift-right (conclusion)

# ar0 ≤ m0 ⊦ copy(ar, m, ar0 + ar1, m0, m1) = ar0 + copy(ar, m, ar1, m0 - # ar0, m1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 2:
m0 = n0 + # ar0, # ar0 ≤ m0 ⊦ copy(ar, m, ar0 + ar1, m0, m1) = ar0 + copy(ar, m, ar1, n0, m1)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [m0, # ar0, n]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: m0, # ar0, n