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Proof step 31 from proof copy2append (previous step)

# ar1 = (n2 + m) + n1, n3 < n2 + m, n1 < # ar1, n3 < # subarray(ar0, n0, m) + # subarray(ar1, n1 + m, n2), m + n1 ≤ # ar1, n0 + m ≤ # ar0, n1 + m ≤ # ar1, m ≤ n3, # subarray(ar0, n0, m) ≤ n3 ⊦ ar1[n3 + n1] = subarray(ar1, n1 + m, n2)[n3 - # subarray(ar0, n0, m)], n2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
# ar1 = (n2 + m) + n1, n1 < # ar1, n3 < n2 + m, n3 < m + n2, m ≤ n3, n1 + m ≤ # ar1, n0 + m ≤ # ar0, m + n1 ≤ # ar1 ⊦ ar1[n3 + n1] = subarray(ar1, n1 + m, n2)[n3 - m], n2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ # subarray(ar, m, n) = n; (s)