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Proof step 32 from proof copy2append0 (previous step)

# ar1 = (n2 + n1) + n0, n0 < # ar1, n0 + n1 < # ar1, n3 < n2 + n1, n3 < # subarray(ar0, 0, n1) + # subarray(ar1, n0 + n1, n2), n1 ≤ n3, n1 ≤ # ar0, # subarray(ar0, 0, n1) ≤ n3 ⊦ ar1[n3 + n0] = subarray(ar1, n0 + n1, n2)[n3 - # subarray(ar0, 0, n1)], n2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
# ar1 = (n2 + n1) + n0, n3 < n2 + n1, n0 + n1 < # ar1, n0 < # ar1, n3 < n1 + n2, n1 ≤ # ar0, n1 ≤ n3 ⊦ ar1[n3 + n0] = subarray(ar1, n0 + n1, n2)[n3 - n1], n2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ # subarray(ar, m, n) = n; (s)