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Proof step 6 from proof copy2append00 (
previous step
)
⊦ n1 ≤ # ar0 ∧ n0 + n1 ≤ # ar1 → copy(ar0, 0, ar1, n0, n1) = subarray(ar1, 0, n0) + subarray(ar0, 0, n1) + subarray(ar1, n0 + n1, # ar1 - n0 - n1)
Lemma
copy2append0