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Proof step 27 from proof fill-append-shift (previous step)

n1 < # ar1 ⊦ (n0 ≤ n1 ∧ n1 < n0 + m ⊃ a;ar1[n1]) = fill(ar1, a, n0, m)[n1]

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: array-copy name: at-fill-h seq: ⊦ n < # ar → fill(ar, a, m0, m1)[n] = (m0 ≤ n ∧ n < m0 + m1 ⊃ a;ar[n]) subst: [n, m1, m0, a, ar] → [n1, m, n0, a, ar1] flags: <all paths>

Additional information

Used terms: n1, m, n0, a, ar1